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#242 ll Show that ∀x [P(x) → Q(x)] ∧ ∀x [Q(x) → R(x)] ⇒ ∀x [P(x) → R(x)]

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#242 ll Show that ∀x [P(x) → Q(x)] ∧ ∀x [Q(x) → R(x)] ⇒ ∀x [P(x) → R(x)]

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